Size and shape of aggregates directly influence the quantity of cement required in concrete mix and hence ultimately the economy of concrete. Largest coarse aggregates should be given priority according to the feasibility of structure. According to IS-456; the maximum size of aggregates that can be used in PCC and RCC are:Get price

Weight of Coarse Aggregates = volume x density, Density of Coarse Aggregates = 1520 kg/m^3 Weight of Coarse Aggregates = 0.84 x 1520 = 1276.8 kg (1.28 tonnes) The above calculation you can use for all Grade of Concrete but just you have to put the different Grade of concrete like M10, M 15, M20, M25 etc. just here with grade of concrete Get price

2021-2-8M-5 and M-7.5 grades of concrete may be used for lean concrete bases and simple foundations for masonry walls. Grades of concrete lower than M-15 shall not be used in reinforced concrete. Previously IS : 456 – 1964 specified the following grades of concrete M-100, M-150, M-200, M-250, M-300, M-350 and M-400.Get price

2007-5-1However the cement amount required for the high compressive strength concrete was considered high and consequently the dosage of the CC concrete was changed from 325 kg to 300 kg of cement/m 3 of concrete with 0.55 effective water/cement ratio. As it is mentioned above the recycled aggregates were used wet and this produced controllable Get price

where V c is the volume of concrete. W, C, F a and C a are the masses of water, cement, fine aggregates and coarse aggregates respectively. Density of cement = 1500 kg/m 3, fine aggregates = 1700 kg/m 3 and coarse aggregates = 1650 kg/m 3. So, Weight of cement C = 0.25 x 1500 = 375kg Weight of Fine aggregates F a = 0.25 x 1700 = 425 kg. Read MoreGet price

2020-5-2Quantity of Water is added in M20 grade concrete (All grades):-As I was already given a detailed explanation about how to find out the quantity of Cement, Sand and Aggregate required for different grades of concrete. Here you can learn about the quantity of water is added in M20 grade concrete (all grades).Get price

Example computation: Based on the required 20Mpa comp. strength (Fc') of a column, water-cement ratio is 0.60 Step 5. Required cement content C = W (W / C) Example computation: C = 184 / (0.6) = 306.67 kg/m 3 Step 6. Quantity of coarse aggregates o Percent of Coarse Aggregate (C.A.) inside a well compacted concrete mix.Get price

Quantities of materials for concrete such as cement, sand and aggregates for production of required quantity of concrete of given mix proportions such as 1:2:4 (M15), 1:1.5: 3 (M20), 1:1:2 (M25) can be calculated by absolute volume method. This method is based on the principle that the volume of fully compacted concrete is equal to []Get price

2019-9-13The mix proportion of concrete is taken as 1:3:6 i.e. one part cement, three parts sand and 6 parts aggregates. Now, total parts = 1+3+6 = 10 parts. The quantity of cement, sand and aggregate will be calculated as follow :-CEMENT: = 1/10 x 1.54 = 0.154 m 3. Now, it is required to convert the quantity to bags.Get price

For easier calculation we will use M15 grade concrete. For M15 concrete. Cement : Sand : Aggregates = 1:2:4. Calculation For Floor And Ceilings: Volume of floor/ceiling = 10x10x1 (assuming thickness of slab =1ft)= 100 cft. 1 bag of cement contains 50 kg cement = 1.71cft. For M15 concrete (1:2:4), Sand required for 1 bag cement = 1.71 x 2 = 3.42 cftGet price

2020-10-10example - I have to put 750 kg of 20 mm aggregates in concrete. if its specific gravity becomes low due to higher porosity or voids in it. the volume which it makes to same weight will get increase and will make my concrete more than a cum for same mix design. same way if its specific gravity increases my volume will become less for same Get price

Therefore, Density of aggregate = 1450 – 1750 kg/ m 3 . Quantity of aggregate in cubic feet = 3 x 1.54 /5.5 x 35.3147 = 29.66 cu.ft. Water: For M20, 30 liters of water per 50kg cement . Total amount of water required = 30 x 403.2 / 50 = 241.92 litre. 8.064 bags of cement required for 1 cu.m of M20 grade concrete. 630 kg of Sand required for Get price

2021-2-24The dry volume of concrete mixture is always greater than the wet volume. The ratio of dry volume to the wet volume of concrete is 1.54. So 1.54 Cum of dry materials (cement, sand and aggregate) is required to produce 1 Cum of concrete. Volume of Cement required = 1/(1+2+4) X 1.54 = 1/7 X 1.54 = 0.22 CumGet price

2007-5-1However the cement amount required for the high compressive strength concrete was considered high and consequently the dosage of the CC concrete was changed from 325 kg to 300 kg of cement/m 3 of concrete with 0.55 effective water/cement ratio. As it is mentioned above the recycled aggregates were used wet and this produced controllable Get price

2017-8-5AGGREGATES FOR CONCRETE E1-3 sieve and predominantly retained on the 75 m (No. 200) sieve is called "fine aggregate" or "sand," and larger aggregate is called "coarse aggregate." Coarse aggregate may be available in several different size groups, such as 19 to 4.75 mm (3/4 in.Get price

2015-10-262.36 mm sieve. The quantity used for spreading shall be 0.09 cubic metre per 10 square metre area. B.Premixed Seal Coat: a thin application of fine aggregates premixed with bituminous binder The quantity of bitumen shall be 9.8 kg and 6.8 kg per 10 m 2 area for type A and type B seal coat respectively SEAL COATGet price

2015-10-262.36 mm sieve. The quantity used for spreading shall be 0.09 cubic metre per 10 square metre area. B.Premixed Seal Coat: a thin application of fine aggregates premixed with bituminous binder The quantity of bitumen shall be 9.8 kg and 6.8 kg per 10 m 2 area for type A and type B seal coat respectively SEAL COATGet price

2019-7-1average density 1724.66 kg/m3, but we have to reduce the density of concrete to nearly equals to density of water, so it is to be required that reduce the quantity of crush sand and that's why we reduced the quantity of crushed sand and also replaced it with pumice sand passing through IS sieve of size 4.75 mm. in next sample.Get price

For easier calculation we will use M15 grade concrete. For M15 concrete. Cement : Sand : Aggregates = 1:2:4. Calculation For Floor And Ceilings: Volume of floor/ceiling = 10x10x1 (assuming thickness of slab =1ft)= 100 cft. 1 bag of cement contains 50 kg cement = 1.71cft. For M15 concrete (1:2:4), Sand required for 1 bag cement = 1.71 x 2 = 3.42 cftGet price

2016-10-4Concrete aggregates should confirm to specified values as per standard specification. The quality of concrete is affected by different physical and mechanical properties of aggregate, i.e. shape, grading, durability, specific gravity and water absorption etc. these properties of aggregated should be tested before using it for concrete production.Get price

2018-8-3CALCULATION FOR AGGREGATE QUANTITY; Consider volume of concrete = 1m 3 . Dry Volume of Concrete = 1 x 1.54 = 1.54 m 3. Aggregate = (3/5.5) x 1.54 = 0.84 m 3 ∴ 3 is a part of cement, 5.5 is sum of ratio. Density of Aggregate is 1500/m 3 Calculation for KG = 0.84 x 1500 = 1260 kg. As we know that 1 m3 = 35.31 CFTGet price

2019-8-26– the quantity of concrete required (m 3) and delivery address – the standard strength grade (if applicable compression, flexural, indirect tensile) – the particle density, maximum nominal size and grading of the coarse aggregate (ii accordance with AS2758.1) or alternatively, the source of aggregate supplyGet price

2017-8-29The characteristics of the aggregates were established in order to study their possible appli-cation in concrete production. After analysis, the dosage procedure was carried out. Four types of concretewereproduced:concretewithoutrecycled aggregate, called control concrete (HC), concrete with 25% of recycled coarse aggregates (HR25),Get price

2019-6-11Therefore, total concrete volume required is 1.57 m 3. Calculation of Volume of Cement in 1m 3 of Concrete:-The Quantity of Cement in Concrete will be measured with the following formula :-Volume of Cement = Cement⁄Cement+Sand+Aggregate x 1.57 = 1 / 1+1.5+3 x 1.57 = 0.28 m 3. 1m 3 of cement = 1440 kgs 0.28m 3 of cement = 1440 x 0.28 = 403.2 kgsGet price

Concrete is basically a heterogeneous mixture, which consists of cement, sand, stone aggregates and water. For a big project, where the higher grade of concrete is used, mix design is must to determine the quantities of the materials required to maintain the grade. But when a lesser grade of concrete is used, quantity analysis for Cement, Sand And Aggregate is done by some basic Get price

2021-2-172) Work out the type, size and number of machines required for producing requisite quantitities of aggregates and concrete. Solution: Average rate of placement of concrete: Total quantity to be placed in 4 years = 5,60,000 m 3. Average quantity to be placed in a year = 1,40,000 m 3. Maximum quantity to be placed in a year = 2,10,000 m 3Get price

2017-8-5AGGREGATES FOR CONCRETE E1-3 sieve and predominantly retained on the 75 m (No. 200) sieve is called "fine aggregate" or "sand," and larger aggregate is called "coarse aggregate." Coarse aggregate may be available in several different size groups, such as 19 to 4.75 mm (3/4 in.Get price

Aggregates are one of the most important constituents of the concrete which give body to the concrete and also reduce shrinkage. Aggregates occupy 60 to 80 % of total volume of concrete. So, we can say that one should know definitely about the aggregates in depth to study more about concrete. Aggregate may be natural, []Get price

2021-2-25Total weight of concrete ingredients = 50+115+209+27.5 = 401.5 say 400 kg. Density of concrete = 2400 kg/cum. So, 1 bag of cement produces = 400/2400 = 0.167 cum. No. of bags required for 01 cum of concrete = 1/0.167 = 5.98 bags ~ 6 bags. From above, if the concrete mix is 1:2:4, to get a cubic meter of concrete we require. 1.Cement = 6 bags Get price

where V c is the volume of concrete. W, C, F a and C a are the masses of water, cement, fine aggregates and coarse aggregates respectively. Density of cement = 1500 kg/m 3, fine aggregates = 1700 kg/m 3 and coarse aggregates = 1650 kg/m 3. So, Weight of cement C = 0.25 x 1500 = 375kg Weight of Fine aggregates F a = 0.25 x 1700 = 425 kg. Read MoreGet price

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